IP and EA of 'F' are 17.24 and 3.45 ev/atom resp. EN of 'F' will be :-

Options

A. 2.7
B. 3.7
C. 4.07
D. 6.7

Answer

To find the electronegativity (EN) of fluorine (F) using the given ionization potential (IP) and electron affinity (EA), we can use both the Mulliken scale and the Pauling scale. Here’s how to solve the problem step by step:

### Step 1: Identify the Given Values
- Ionization Potential (IP) of F = 17.24 eV/atom
- Electron Affinity (EA) of F = 3.45 eV/atom

### Step 2: Calculate Electronegativity using the Mulliken Scale
The formula for electronegativity (EN) using the Mulliken scale is:
\[ EN = \frac{IP + EA}{2} \]
Substituting the given values:
\[ EN = \frac{17.24 + 3.45}{2} \]
Calculating the sum:
\[ EN = \frac{20.69}{2} = 10.345 \]

### Step 3: Calculate Electronegativity using the Pauling Scale
The formula for electronegativity (EN) using the Pauling scale is:
\[ EN = \frac{IP + EA}{5.6} \]
Substituting the given values:
\[ EN = \frac{17.24 + 3.45}{5.6} \]
Calculating the sum:
\[ EN = \frac{20.69}{5.6} \approx 3.69 \]

### Step 4: Conclusion
From our calculations:
- Using the Mulliken scale, the electronegativity of fluorine is approximately 10.345.
- Using the Pauling scale, the electronegativity of fluorine is approximately 3.69.

Since the question does not specify which scale to use, we can conclude that the most relevant value is from the Pauling scale, which is approximately **3.7**.

### Final Answer
The electronegativity of fluorine (F) is approximately **3.7**.

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