Correct order of `IP` is ?

Options

A. `NaltMggtAlltSi`
B. `NagtMgltAlgtSi`
C. `NagtMggtAlltSi`
D. `NagtMggtAlgtSi`

Answer

To determine the correct order of ionization potential (IP) for the elements sodium (Na), magnesium (Mg), aluminum (Al), and silicon (Si), we need to analyze their electronic configurations and the general trends in ionization energy across a period in the periodic table.

### Step-by-Step Solution:

1. **Understand Ionization Potential (IP)**:
- Ionization potential (or ionization energy) is the energy required to remove an electron from a neutral atom in its gaseous state.

2. **Identify the Elements and Their Groups**:
- Sodium (Na) is in Group 1.
- Magnesium (Mg) is in Group 2.
- Aluminum (Al) is in Group 13.
- Silicon (Si) is in Group 14.

3. **Write the Electronic Configurations**:
- Sodium (Na): 1s² 2s² 2p⁶ 3s¹
- Magnesium (Mg): 1s² 2s² 2p⁶ 3s²
- Aluminum (Al): 1s² 2s² 2p⁶ 3s² 3p¹
- Silicon (Si): 1s² 2s² 2p⁶ 3s² 3p²

4. **General Trend of Ionization Energy**:
- Ionization energy generally increases across a period from left to right due to increasing nuclear charge, which holds the electrons more tightly.

5. **Analyze the Specific Case of Mg and Al**:
- Although Al is to the right of Mg, it has a lower ionization energy than Mg. This is due to the fact that Mg has a fully filled 3s subshell, which is more stable and requires more energy to remove an electron compared to the 3p electron in Al.

6. **Determine the Correct Order**:
- Based on the analysis:
- Silicon (Si) has the highest ionization energy because it is further to the right and has a higher nuclear charge.
- Aluminum (Al) has a lower ionization energy than Magnesium (Mg) due to the reasons discussed.
- Magnesium (Mg) has a higher ionization energy than Sodium (Na) because it has a fully filled 3s subshell.
- Sodium (Na) has the lowest ionization energy.

Therefore, the correct order of ionization potential is:
\[ \text{Si} > \text{Al} > \text{Mg} > \text{Na} \]

### Final Answer:
The correct order of ionization potential (IP) is:
\[ \text{Si} > \text{Al} > \text{Mg} > \text{Na} \]