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Match the column {:(Column-I,,,,Column...

Match the column
`{:(Column-I,,,,Column-II),((a)C_(2)H_(2),,,,(P) sp^(3)"dhybridisation"),(SO_(2),,,,(Q)sp^(3)"hybridisation"),(( c)I_(3)^(-),,,,(R)sp^(2)"hybridisation"),((d)NH_(4)^(+),,,,(S)sp"hybridisation"):}`

A

(a)S (b)P ( c)R (d) Q

B

(a)P (b)S ( c)R (d)Q

C

(a)S (b)R (c )P (d)Q

D

(a)R (b)S ( c)P (d)Q

Text Solution

AI Generated Solution

The correct Answer is:
To solve the matching question regarding the hybridization of different molecules, we will analyze each molecule in Column-I and determine its corresponding hybridization from Column-II. ### Step-by-Step Solution: 1. **Identify the hybridization of C₂H₂ (Acetylene)**: - C₂H₂ has a triple bond between the two carbon atoms. - Each carbon atom in a triple bond uses one s orbital and one p orbital to form two π bonds and one σ bond. - Therefore, the hybridization for C₂H₂ is **sp**. - **Match**: (a) C₂H₂ → (S) sp hybridization. 2. **Identify the hybridization of SO₂ (Sulfur Dioxide)**: - In SO₂, sulfur is the central atom with two double bonds to oxygen and one lone pair. - The steric number (number of bonds + lone pairs) is 3 (2 double bonds + 1 lone pair). - This corresponds to **sp² hybridization**. - **Match**: (b) SO₂ → (R) sp² hybridization. 3. **Identify the hybridization of I₃⁻ (Triiodide Ion)**: - In I₃⁻, iodine is the central atom with three bonds to iodine atoms and two lone pairs. - The steric number is 5 (3 bonds + 2 lone pairs). - This corresponds to **sp³d hybridization**. - **Match**: (c) I₃⁻ → (P) sp³d hybridization. 4. **Identify the hybridization of NH₄⁺ (Ammonium Ion)**: - In NH₄⁺, nitrogen is the central atom with four single bonds to hydrogen atoms and no lone pairs. - The steric number is 4 (4 bonds). - This corresponds to **sp³ hybridization**. - **Match**: (d) NH₄⁺ → (Q) sp³ hybridization. ### Final Matches: - (a) C₂H₂ → (S) sp hybridization - (b) SO₂ → (R) sp² hybridization - (c) I₃⁻ → (P) sp³d hybridization - (d) NH₄⁺ → (Q) sp³ hybridization ### Summary of Matches: - A → S - B → R - C → P - D → Q ### Correct Option: The correct answer is **Option 3**.
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Sulphur is sp^2 hybridised in

The d-orbitals involved in sp^(3)d hybridisation is: