Match the column
`{:("Compound",,,,"No. of" sigma & pi "Bonds"),((a)H_(2)S_(2)O_(3),,,,(P)6sigma&2pi),((b)H_(2)SO_(5),,,,(Q)11sigma&4pi),((c )H_(2)S_(2)O_(8),,,,(R)9sigma&4pi),((d)H_(2)S_(2)O_(6),,,,(S)7sigma&pi2pi):}`

Options

A. (a)S (b)P (c )Q (d)R
B. (a)P (b)S (c )Q (d)R
C. (a)P (b)Q (c )R (d)S
D. (a)Q (b)S (c ) (d)R

Explanation

To solve the problem of matching the compounds with their respective number of sigma and pi bonds, we will analyze each compound step by step.

### Step-by-Step Solution:

1. **Identify the Compound H₂S₂O₃:**
- Draw the Lewis structure:
- S double bond O, S single bond O, and two OH groups.
- Count the bonds:
- Sigma bonds: 6 (from S-O and O-H)
- Pi bonds: 2 (from the S=O double bonds)
- **Result:** H₂S₂O₃ has 6 sigma and 2 pi bonds.

2. **Identify the Compound H₂SO₅:**
- Draw the Lewis structure:
- S double bond O, S single bond O, and two OH groups.
- Count the bonds:
- Sigma bonds: 7 (from S-O and O-H)
- Pi bonds: 2 (from the S=O double bonds)
- **Result:** H₂SO₅ has 7 sigma and 2 pi bonds.

3. **Identify the Compound H₂S₂O₈:**
- Draw the Lewis structure:
- Two S atoms, each with double bonds to O and connected to OH groups.
- Count the bonds:
- Sigma bonds: 11 (from S-O and O-H)
- Pi bonds: 4 (from the S=O double bonds)
- **Result:** H₂S₂O₈ has 11 sigma and 4 pi bonds.

4. **Identify the Compound H₂S₂O₆:**
- Draw the Lewis structure:
- Two S atoms, each with double bonds to O and connected to OH groups.
- Count the bonds:
- Sigma bonds: 9 (from S-O and O-H)
- Pi bonds: 4 (from the S=O double bonds)
- **Result:** H₂S₂O₆ has 9 sigma and 4 pi bonds.

### Summary of Results:
- (a) H₂S₂O₃ → 6 sigma & 2 pi (P)
- (b) H₂SO₅ → 7 sigma & 2 pi (S)
- (c) H₂S₂O₈ → 11 sigma & 4 pi (Q)
- (d) H₂S₂O₆ → 9 sigma & 4 pi (R)

### Final Matching:
- (a) → (P)
- (b) → (S)
- (c) → (Q)
- (d) → (R)