Match the column
Compound Shape
`{:((a)XeO_(2)F_(2),,,,(P)"Linear"),((b)XeF_(5)^(-),,,,(Q)"Square planar"),((c )I_(3)^(-),,,,(R)"See-saw"),((d)XeF_(4),,,,(S)"Pentagonal planar"):}`

Options

A. (a)R (b)S (c )P (d)Q
B. (a)R (b)S (c )Q (d)P
C. (a)P (b)S ( c)Q (d)R
D. (a)S (b)Q ( c)P (d)R

Answer

To solve the problem of matching the compounds with their respective shapes, we will analyze each compound one by one based on their molecular geometry.

### Step-by-Step Solution:

1. **Identify the shape of XeO₂F₂:**
- The compound XeO₂F₂ has two oxygen atoms and two fluorine atoms attached to the central xenon atom.
- The molecular geometry can be determined by considering the lone pairs and the arrangement of the bonded atoms.
- XeO₂F₂ has a trigonal bipyramidal arrangement, but due to the presence of lone pairs, the shape is distorted to a **C-shaped (or seesaw)** structure.
- **Match:** (a) XeO₂F₂ → (R) "C-shaped"

2. **Identify the shape of XeF₅⁻:**
- For XeF₅⁻, there are five fluorine atoms bonded to xenon with a negative charge.
- The geometry is based on a pentagonal bipyramidal arrangement, and since it has a negative charge, it adopts a **pentagonal planar** shape.
- **Match:** (b) XeF₅⁻ → (S) "Pentagonal planar"

3. **Identify the shape of I₃⁻:**
- The I₃⁻ ion consists of three iodine atoms with two lone pairs on the central iodine atom.
- The arrangement of these atoms leads to a **linear** shape.
- **Match:** (c) I₃⁻ → (P) "Linear"

4. **Identify the shape of XeF₄:**
- In XeF₄, there are four fluorine atoms bonded to xenon and two lone pairs on the xenon atom.
- The molecular geometry is square planar due to the arrangement of the fluorine atoms around the xenon.
- **Match:** (d) XeF₄ → (Q) "Square planar"

### Final Matches:
- (a) XeO₂F₂ → (R) "C-shaped"
- (b) XeF₅⁻ → (S) "Pentagonal planar"
- (c) I₃⁻ → (P) "Linear"
- (d) XeF₄ → (Q) "Square planar"

### Summary of Matches:
- A: R
- B: S
- C: P
- D: Q