Match column-I and Column-II
`{:(Column-I,,,,Column-II),((A)SF_(4),,,,(1)"Tetrahedral"),((B)BrF_(3),,,,"(2)Pyramidal"),((C )BrO_(3)^(-),,,,(3)See-saw),((D)NH_(4),,,,(4)Bent-T):}`

Options

A. A (3),B (2),C (1), D(4)
B. A(3), B(4), C(2), (D)1
C. A(2),B(4),C(3), (D)1
D. A(1),B(4), C(2),D(3)

Answer

To solve the problem of matching Column-I with Column-II, we need to determine the molecular geometry of each compound listed in Column-I and then match it with the corresponding shape in Column-II. Here’s a step-by-step breakdown:

### Step 1: Analyze SF₄
- **Molecule**: SF₄ (Sulfur Tetrafluoride)
- **Valence Electrons**:
- Sulfur (S): 6 electrons
- Fluorine (F): 7 electrons × 4 = 28 electrons
- Total = 6 + 28 = 34 electrons
- **Hybridization**:
- Divide by 8: 34/8 = 4.25 (4 bond pairs and 1 lone pair)
- Hybridization = SP³D (5 regions of electron density)
- **Shape**: With 4 bond pairs and 1 lone pair, the shape is **Seesaw**.
- **Match**: A matches with (3) Seesaw.

### Step 2: Analyze BrF₃
- **Molecule**: BrF₃ (Bromine Trifluoride)
- **Valence Electrons**:
- Bromine (Br): 7 electrons
- Fluorine (F): 7 electrons × 3 = 21 electrons
- Total = 7 + 21 = 28 electrons
- **Hybridization**:
- Divide by 8: 28/8 = 3.5 (3 bond pairs and 2 lone pairs)
- Hybridization = SP³D (5 regions of electron density)
- **Shape**: With 3 bond pairs and 2 lone pairs, the shape is **T-shaped**.
- **Match**: B matches with (4) T-shaped.

### Step 3: Analyze BrO₃⁻
- **Molecule**: BrO₃⁻ (Bromate Ion)
- **Valence Electrons**:
- Bromine (Br): 7 electrons
- Oxygen (O): 6 electrons × 3 = 18 electrons
- Additional electron due to negative charge = 1
- Total = 7 + 18 + 1 = 26 electrons
- **Hybridization**:
- Divide by 8: 26/8 = 3.25 (3 bond pairs and 1 lone pair)
- Hybridization = SP³ (4 regions of electron density)
- **Shape**: With 3 bond pairs and 1 lone pair, the shape is **Pyramidal**.
- **Match**: C matches with (2) Pyramidal.

### Step 4: Analyze NH₄⁺
- **Molecule**: NH₄⁺ (Ammonium Ion)
- **Valence Electrons**:
- Nitrogen (N): 5 electrons
- Hydrogen (H): 1 electron × 4 = 4 electrons
- Total = 5 + 4 = 9 electrons (considering the positive charge)
- **Hybridization**:
- Divide by 8: 9/8 = 1.125 (4 bond pairs and 0 lone pairs)
- Hybridization = SP³ (4 regions of electron density)
- **Shape**: With 4 bond pairs and no lone pairs, the shape is **Tetrahedral**.
- **Match**: D matches with (1) Tetrahedral.

### Final Matches
- A matches with (3) Seesaw
- B matches with (4) T-shaped
- C matches with (2) Pyramidal
- D matches with (1) Tetrahedral

### Summary of Matches:
- A → 3
- B → 4
- C → 2
- D → 1

### Correct Option:
The correct matches are A3, B4, C2, D1.

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