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The true statement from the following ar...

The true statement from the following are

A

`PH_(5),NCl_(5)` and `BiCl_(5)` do not exist

B

`I_(3)^(-)` has bent geometry

C

`XeF_(4)` is polar molecule

D

`O_(2)` and `O_(2)^(-2)` has same bond order

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AI Generated Solution

The correct Answer is:
To determine the true statements from the given options, we will analyze each statement one by one. ### Step 1: Analyze the first statement - "PH5, NCl5, and BiCl5 do not exist." - **PH5**: Phosphorus (P) can utilize its s, p, and d orbitals for bonding. However, due to the small size of hydrogen, the d-orbitals of phosphorus cannot effectively overlap with hydrogen's orbitals, making the formation of PH5 impossible. - **NCl5**: Nitrogen (N) has an atomic number of 7, and its small size limits it to forming a maximum of three bonds (as seen in NH3). Therefore, N cannot form five bonds, making NCl5 non-existent. - **BiCl5**: Bismuth (Bi), being larger than nitrogen and chlorine, experiences steric hindrance due to its size and the size of chlorine atoms. This steric hindrance prevents the formation of BiCl5. - **Conclusion**: The first statement is true. ### Step 2: Analyze the second statement - "I3- has bent geometry." - **I3-**: The ion consists of three iodine atoms. The central iodine atom is bonded to two terminal iodine atoms. The geometry of I3- is linear due to the arrangement of the three iodine atoms and the presence of a negative charge, which does not affect the linearity. - **Conclusion**: The second statement is false. ### Step 3: Analyze the third statement - "XeF4 is a polar molecule." - **XeF4**: Xenon (Xe) has 8 valence electrons. In XeF4, there are four fluorine atoms bonded to xenon, and two lone pairs of electrons on xenon. The symmetrical arrangement of the four fluorine atoms around xenon leads to the cancellation of dipole moments, resulting in a non-polar molecule. - **Conclusion**: The third statement is false. ### Step 4: Analyze the fourth statement - "O2 and O2 2- have the same bond order." - **O2**: Molecular oxygen has a bond order of 2 (double bond). - **O2 2-**: The peroxide ion has two additional electrons, leading to a bond order of 1 (single bond). - **Conclusion**: The fourth statement is false. ### Final Conclusion: The only true statement is the first one: "PH5, NCl5, and BiCl5 do not exist." ---
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ALLEN-CHEMISTRY AT A GLANCE-INORGANIC CHEMISTRY
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  3. The true statement from the following are

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  4. The bond order for Ne2 and C2, respectively are

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  5. Back Bonding

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  6. The bond angle in H(2)O molecule is .. .....

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  7. What is the order of stability of N(2) and its ions ?

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  8. Which of the following have identical bond order?

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  9. In XeF(2), XeF(4) and XeF(6) the number of lone pairs on Xe is respect...

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  10. Which one of the following compounds is the most soluble in water?

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  11. The correct order of N-O bond lengths in NO, NO2^- , NO3^- and N2O4 is

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  12. The correct order of A-O-A bond angle of (A=H,F or Cl)

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  13. There are some species given below :- {:((a)O(2)^(+),,,,(b)CO),((c)B...

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  14. Which of the following has fractional bond order ?

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  15. When AgNO(3) is heated strongly, the products fomed are

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  16. Among the carbonates of alkali metals which one has highest thermal st...

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  17. Which of the following order is not correct?

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  18. The state of hybridisation for the transition state of hydrolysis mech...

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  19. The dipole moment of AX(3), BX(3)and CX(3) are 1.5 D, 0.5 D and 0 D re...

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  20. Arrange O(2),O(2)^(-),O(2)^(2-),O(2)^(+) in increasing order of bond e...

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