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Which of the following molecule is polar...

Which of the following molecule is polar and non-planar

A

`XeF_(4)`

B

`XeF_(5)^(-)`

C

`CH_(2)F_(2)`

D

`ClF_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given molecules is polar and non-planar, we will analyze each option step by step. ### Step 1: Analyze Option A - XeF4 - **Valence Electrons Calculation**: - Xenon (Xe) has 8 valence electrons. - Each Fluorine (F) has 7 valence electrons, and there are 4 Fluorine atoms: 4 × 7 = 28. - Total = 8 + 28 = 36 valence electrons. - **Lewis Structure**: - 36 valence electrons divided by 8 (for the octet rule) gives us 4 bond pairs and 2 lone pairs. - The arrangement is square planar due to the 4 bond pairs and 2 lone pairs. - **Polarity**: - The molecule is symmetrical, and the dipole moments cancel out, resulting in a net dipole moment of 0. - **Conclusion**: XeF4 is non-polar and planar. ### Step 2: Analyze Option B - XeF5^- - **Valence Electrons Calculation**: - Xenon (Xe) has 8 valence electrons. - 5 Fluorine atoms contribute 28 valence electrons (5 × 7 = 35). - The negative charge adds 1 electron: 8 + 35 + 1 = 44 valence electrons. - **Lewis Structure**: - 44 valence electrons divided by 8 gives us 5 bond pairs and 2 lone pairs. - The shape is distorted octahedral due to the presence of lone pairs. - **Polarity**: - The molecule is non-planar, and the dipole moments do not cancel out completely, resulting in a net dipole moment that is not equal to 0. - **Conclusion**: XeF5^- is polar and non-planar. ### Step 3: Analyze Option C - CH2F2 - **Valence Electrons Calculation**: - Carbon (C) has 4 valence electrons, and each Hydrogen (H) has 1 (2 × 1 = 2), and each Fluorine (F) has 7 (2 × 7 = 14). - Total = 4 + 2 + 14 = 20 valence electrons. - **Lewis Structure**: - The structure has 2 bond pairs with H and 2 bond pairs with F, leading to a tetrahedral shape. - **Polarity**: - The molecule is polar due to the presence of F atoms, but it is not non-planar; it is tetrahedral. - **Conclusion**: CH2F2 is polar but planar. ### Step 4: Analyze Option D - ClF3 - **Valence Electrons Calculation**: - Chlorine (Cl) has 7 valence electrons, and each Fluorine (F) has 7 (3 × 7 = 21). - Total = 7 + 21 = 28 valence electrons. - **Lewis Structure**: - The structure has 3 bond pairs and 2 lone pairs, leading to a T-shaped molecular geometry. - **Polarity**: - The T-shaped structure is polar, but it is also non-planar due to the presence of lone pairs. - **Conclusion**: ClF3 is polar and non-planar. ### Final Conclusion After analyzing all options: - **Option A**: Non-polar and planar. - **Option B**: Polar and non-planar. - **Option C**: Polar but planar. - **Option D**: Polar and non-planar. Thus, the correct answer is **Option B (XeF5^-)** and **Option D (ClF3)** are both polar and non-planar. However, since the question asks for one, we conclude with **Option B** as the primary answer.
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