The correct IUPAC name of `[Pt(NH_(3))_(2)Cl_(4)]` is

Options

A. Diamminetetrachloroplatinum (II)
B. Diamminedichloridoplatinum (IV)
C. Diamminedichloridoplatinum (0)
D. Diamminetetrachloroplatinum (IV)

Answer

To determine the correct IUPAC name of the coordination compound \([Pt(NH_3)_2Cl_4]\), we will follow these steps:

### Step 1: Identify the Central Metal Atom
The central metal atom in the given compound is platinum (Pt).

### Step 2: Identify the Ligands
The ligands attached to the platinum are:
- Ammonia (NH3), which is a neutral ligand and is named as "amine".
- Chloride ions (Cl−), which are anionic ligands and are named as "chloro".

### Step 3: Count the Number of Each Type of Ligand
- There are 2 ammonia ligands, so we will use the prefix "di-" to indicate this.
- There are 4 chloride ligands, so we will use the prefix "tetra-" to indicate this.

### Step 4: Order of Naming Ligands
When naming the ligands, we follow the alphabetical order:
- "chloro" comes before "amine" in alphabetical order.

### Step 5: Combine the Ligands with the Central Metal
Now we combine the names of the ligands with the name of the central metal:
- The ligands will be named as "tetrachloro" for the 4 chloride ions and "diamine" for the 2 ammonia ligands.
- The name of the central metal is "platinum".

### Step 6: Determine the Oxidation State of the Central Metal
To find the oxidation state of platinum in this complex:
- Let the oxidation state of platinum be \(x\).
- The overall charge of the complex is neutral (0).
- The contribution from the ligands is:
- From 2 NH3: \(2 \times 0 = 0\) (neutral)
- From 4 Cl: \(4 \times (-1) = -4\)

Setting up the equation:
\[ x + 0 - 4 = 0 \]
\[ x = +4 \]

### Step 7: Write the Final IUPAC Name
The final IUPAC name combines all the information:
- Ligands in alphabetical order: "tetrachloro" and "diamine".
- Central metal with oxidation state in Roman numeral: "platinum(IV)".

Thus, the correct IUPAC name of the compound \([Pt(NH_3)_2Cl_4]\) is:
**Tetrachlorodiammineplatinum(IV)**.

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