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CrO(4)^(2-) (yellow) changes to Cr(2)O(7...

`CrO_(4)^(2-)` (yellow) changes to `Cr_(2)O_(7)^(2-)` (oragne) in pH = x and vice - versa in pH = y. Hence, x and y may be -

A

4 and 5

B

4 and 8

C

8 and 4

D

8 and 9

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The correct Answer is:
B
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CrO_(4)^(2-) (yellow) changes to Cr_(2)O_(7)^(2-) (orange) in pH=x and vice-versa in pH=y. Hence, x and y are:

CrO_(4)^(2-) (yellow) changes to Cr_(2)O_(7)^(2-)( orange ) in pH=y . Hence x and y are :

Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)

Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)

CrO_(4)^(2-)underset(pH=Y)overset(pH=X)(hArr)Cr_(2)O_(7)^(-2) The pH values of (X) and (Y) are respectively

CrO_(4)^(2-)underset(pH=Y)overset(pH=X)(hArr)Cr_(2)O_(7)^(-2) The pH values of (X) and (Y) are respectively

Cr_(2)O_(7)^(2-)overset(pH=x)rarrCrO_(4)^(2-)overset(pH=y)rarrCr_(2)O_(7)^(2-) x and y can be :

K_(2)Cr_(2)O_(7)+NaoH to CrO_(4)^(2-)

K_(2)Cr_(2)O_(7)+NaoH to CrO_(4)^(2-)

A: In CrO_(5) oxidation state of Cr is +10 R: Cr_(2)O_(7)^(2-) (aq) is yellow in colour

ALLEN-CHEMISTRY AT A GLANCE-INORGANIC CHEMISTRY
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  4. Which is correct

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