IUPAC Name of :
`CH_(2)=CH-underset(CH_(2))underset(||)(C)-C-=CH`

Options

A. 2-Propynyl buta-1,2-diene
B. 4-Methylene hex-5-en-1-yne
C. 3-Methylene pent-1-en-4-yne
D. 2-Vinyl pent-1-en-4-yne

Answer

To determine the IUPAC name of the compound `CH2=CH-CH2-C≡CH`, we can follow these steps:

### Step 1: Identify the longest carbon chain
The first step in naming an organic compound is to identify the longest continuous carbon chain. In this case, the longest chain consists of 5 carbon atoms.

### Step 2: Number the carbon chain
Next, we need to number the carbon atoms in the chain. We will start numbering from the end of the chain that gives the double and triple bonds the lowest possible numbers. Here, we can number the carbon chain as follows:
1. CH2 (1)
2. CH (2)
3. CH2 (3)
4. C (4)
5. C≡CH (5)

### Step 3: Identify the functional groups
In this compound, we have:
- A double bond (alkene) between carbon 1 and carbon 2.
- A triple bond (alkyne) between carbon 4 and carbon 5.

### Step 4: Assign locants to the functional groups
We assign locants (numbers) to the double and triple bonds:
- The double bond is at position 1 (1-ene).
- The triple bond is at position 4 (4-yne).

### Step 5: Determine the substituents
In this compound, there is a methylene (-CH2-) group attached to carbon 3.

### Step 6: Combine the information
Now we can combine all the information to write the IUPAC name. The longest chain is pentane (5 carbons), and we have:
- A double bond at position 1 (1-ene).
- A triple bond at position 4 (4-yne).
- A methylene group at position 3.

Thus, the IUPAC name of the compound is **3-methylene-pent-1-ene-4-yne**.

### Final Answer
The IUPAC name of the compound `CH2=CH-CH2-C≡CH` is **3-methylene-pent-1-ene-4-yne**.