Which of the following compound will exhibit geometrical isomerism ?

Options

A. `CH_(2)=CH-CH=CH_(2)`
B. `CH_(2)=CH-CH=CH-CH_(3)`
C. `CH_(2)=CH-CH_(2)-CH=CH_(2)`
D. `CH_(2)=CH-C-=C-CH=CH_(2)`

Answer

To determine which of the given compounds will exhibit geometrical isomerism, we need to analyze each compound based on the presence of different groups around a double bond. Geometrical isomerism occurs when there are two different groups attached to each carbon of the double bond.

### Step-by-Step Solution:

1. **Understand Geometrical Isomerism**:
- Geometrical isomerism occurs in alkenes where there are different substituents attached to the carbon atoms involved in the double bond. The two main types of geometrical isomers are cis (same side) and trans (opposite sides).

2. **Analyze Each Compound**:
- **Option A**:
- Structure: H₂C=CH₂
- Both carbons have two hydrogen atoms attached.
- **Conclusion**: No geometrical isomerism (same groups on both sides).

- **Option B**:
- Structure: CH₂=CH-CH₃ (with a hydrogen and a methyl group on one carbon).
- One carbon has a hydrogen and a methyl group, while the other carbon has two different groups (hydrogen and CH₃).
- **Conclusion**: Yes, it can exhibit geometrical isomerism (can form E and Z isomers).

- **Option C**:
- Structure: H₂C=CH-CH₂-CH₂-CH₃
- The double bond is between two carbons, but both sides have the same groups (hydrogens).
- **Conclusion**: No geometrical isomerism (same groups on both sides).

- **Option D**:
- Structure: CH₂=CH-CH₂-CH₃
- Similar to option C, both sides of the double bond have the same groups.
- **Conclusion**: No geometrical isomerism (same groups on both sides).

3. **Final Conclusion**:
- The only compound that exhibits geometrical isomerism is **Option B**.

### Summary:
- Option A: No geometrical isomerism
- Option B: Exhibits geometrical isomerism (E/Z forms)
- Option C: No geometrical isomerism
- Option D: No geometrical isomerism

**Correct Answer**: Option B