Number of stereoisomers of the given compound is
`CH_(3)-CH=CH-underset(OH)underset(|)(CH)-CH_(3)`

Options

A. (A) 2
B. (B) 3
C. (C) 4
D. (D) 6

Answer

To determine the number of stereoisomers for the compound `CH3-CH=CH(OH)-CH(CH3)`, we will follow these steps:

### Step 1: Identify the Structure
The compound can be represented as:
```
CH3
|
CH3-CH=CH-CH(OH)
```
Here, we have a double bond between the second and third carbon atoms, and a hydroxyl (-OH) group attached to the fourth carbon.

### Step 2: Identify Chiral Centers
A chiral center is a carbon atom that has four different substituents attached to it. In our compound, we need to identify if there are any chiral centers.

- The carbon attached to the -OH group (C4) has four different groups:
1. Hydroxyl group (-OH)
2. Methyl group (-CH3)
3. Hydrogen (H)
4. The rest of the carbon chain (C3)

Thus, C4 is a chiral center.

### Step 3: Determine Optical Isomers
Since we have one chiral center, it can exist in two configurations (R and S). Therefore, we have:
- 2 optical isomers (D and L forms).

### Step 4: Identify Geometrical Isomers
Next, we need to consider the double bond between C2 and C3. This double bond can lead to geometrical (cis/trans) isomerism.

- **Cis Isomer**: The two substituents on the double bond (C2 and C3) are on the same side.
- **Trans Isomer**: The two substituents on the double bond are on opposite sides.

In our case, we can have:
1. **Cis Isomer**: OH and CH3 on the same side.
2. **Trans Isomer**: OH and CH3 on opposite sides.

### Step 5: Count Total Stereoisomers
For each geometrical isomer (cis and trans), we have 2 optical isomers (D and L):
- Cis form: 2 (D and L)
- Trans form: 2 (D and L)

Thus, the total number of stereoisomers is:
- 2 (from cis) + 2 (from trans) = 4 stereoisomers.

### Final Answer
The total number of stereoisomers for the given compound is **4**.

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