Which of the following is correct regarding formation of reactive inter mediate formed on heterolytic bond cleavage :

Options

A. `CH_(3)-S-CH_(3)tooverset(Theta)overset(* *)(C)H_(3)+CH_(3)-overset(Theta)(S)`
B. `CH_(3)-Cutooverset(Theta)overset(* *)(C)H_(3)+overset(Theta)(C)u`
C. `CH_(3)-Cl tooverset(Theta)overset(* *)(C)H_(3)+overset(Theta)(C)l`
D. 1 & 2 both

Answer

To solve the question regarding the correct statement about the formation of reactive intermediates formed on heterolytic bond cleavage, we will analyze each option provided.

### Step-by-Step Solution:

1. **Understanding Heterolytic Bond Cleavage**:
- Heterolytic bond cleavage occurs when a bond breaks unevenly, resulting in the formation of charged species. One atom takes both electrons from the bond, leading to the formation of a cation and an anion.

2. **Analyzing Option A: CH3SCH3**:
- For the molecule CH3SCH3, when heterolytic cleavage occurs, the bond electrons shift towards the more electronegative atom, which is sulfur (S).
- This results in the formation of CH3^+ (methyl cation) and CH3S^- (methylthio anion).
- The option states a different product (TSA negative), which does not match our findings.
- **Conclusion**: Option A is incorrect.

3. **Analyzing Option B: CH3Cu**:
- In the case of CH3Cu, the electrons will shift towards the CH3 group.
- This results in the formation of CH3^- (methyl anion) and Cu^+ (copper cation).
- The products mentioned in this option match our analysis.
- **Conclusion**: Option B is correct.

4. **Analyzing Option C: CH3Cl**:
- For CH3Cl, the electrons will shift towards chlorine (Cl), which is more electronegative.
- This results in the formation of CH3^+ (methyl cation) and Cl^- (chloride anion).
- The products mentioned do not match the expected products.
- **Conclusion**: Option C is incorrect.

5. **Analyzing Option D: A and B both**:
- Since we have established that Option A is incorrect and Option B is correct, this option cannot be true.
- **Conclusion**: Option D is incorrect.

### Final Answer:
- The correct answer regarding the formation of reactive intermediates formed on heterolytic bond cleavage is **Option B**.