`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH-CH_(3)overset(H-Cl)(to)` ?

Options

A. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-underset(Cl)underset(|)(CH)-CH_(3)`
B. `CH_(3)-underset(CH_(3))underset(|)overset(Cl)overset(|)C-CH-underset(CH_(3))underset(|)(CH_(2))-CH_(3)`
C. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-underset(Cl)underset(|)CH=CH_(2)-CH_(3)`
D. `CH_(3)-underset(CH_(3))underset(|)overset(Cl)overset(|)C-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(3)`

Answer

To solve the question regarding the reaction of the compound with HCl, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant Structure**:
The reactant is given as CH₃-CH(CH₃)-C(CH₃)=CH-CH₃. This structure can be broken down as follows:
- A central carbon (C) bonded to two methyl groups (CH₃).
- A double bond (C=C) with another carbon (C) that is also bonded to a methyl group (CH₃).

2. **Ionization of HCl**:
When HCl is introduced, it ionizes into H⁺ and Cl⁻. The H⁺ ion can add to the double bond, leading to the formation of a carbocation.

3. **Formation of Carbocations**:
The H⁺ can attach to either carbon of the double bond:
- If H⁺ adds to the carbon with the methyl group (C1), we get a secondary carbocation.
- If H⁺ adds to the other carbon (C2), we also get a secondary carbocation.
Both carbocations are 2° (secondary) carbocations.

4. **Stability of Carbocations**:
To determine which carbocation is more stable, we analyze hyperconjugation:
- The first carbocation (C1) has more hyperconjugation structures due to the presence of adjacent methyl groups.
- The second carbocation (C2) has fewer hyperconjugation structures.

5. **Select the More Stable Carbocation**:
The carbocation with more hyperconjugation (C1) is more stable. Therefore, this is the one that will form.

6. **Nucleophilic Attack by Cl⁻**:
The Cl⁻ ion will attack the more stable carbocation (C1), leading to the formation of the product.

7. **Write the Product Structure**:
The final product after the nucleophilic attack will be:
- CH₃-CH(CH₃)-C(CH₃)-CH₂-CHCl (where Cl is attached to the carbon that was originally part of the double bond).

8. **Identify the Correct Option**:
Compare the product structure with the provided options. The correct answer matches with the first option.

### Final Answer:
The product formed from the reaction is CH₃-CH(CH₃)-C(CH₃)-CH₂-CHCl.

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