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Which gives ketonic group after hydrobor...

Which gives ketonic group after hydroboration oxidation :

A

`CH_(3)-CH_(2)-C-=CH`

B

C

`C Cl_(3)-C-=CH`

D

`CH_(3)-underset(CH_(3))underset(|)(CH)-C-=CH`

Text Solution

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The correct Answer is:
To determine which compound gives a ketonic group after hydroboration-oxidation, we will analyze each option step by step. ### Step 1: Understand Hydroboration-Oxidation Hydroboration-oxidation is a two-step reaction: 1. **Hydroboration**: A boron hydride (BH3) adds across a double or triple bond. The boron atom attaches to the less substituted carbon atom, while hydrogen attaches to the more substituted carbon atom. 2. **Oxidation**: The boron is replaced by a hydroxyl group (OH) using hydrogen peroxide (H2O2) in a basic medium. ### Step 2: Analyze Each Compound #### Option 1: CH3CH2C≡CH 1. **Hydroboration**: - BH2 adds to the terminal carbon (less substituted), and H adds to the adjacent carbon. - Resulting structure: CH3CH2C=CH2 (double bond formed). 2. **Oxidation**: - Replace BH2 with OH. - Resulting structure: CH3CH2CH2CHO (an aldehyde). 3. **Conclusion**: This option does not yield a ketone. #### Option 2: C6H5C≡CH 1. **Hydroboration**: - BH2 adds to the carbon with the triple bond that is less substituted (the one attached to the phenyl ring), and H adds to the other carbon. - Resulting structure: C6H5C=CH2. 2. **Oxidation**: - Replace BH2 with OH. - Resulting structure: C6H5C(OH)=CH2 (enol form). 3. **Tautomerization**: - Converts to C6H5C=O (an aldehyde). 4. **Conclusion**: This option does not yield a ketone. #### Option 3: CCl3C≡CH 1. **Hydroboration**: - Due to the electron-withdrawing effect of Cl, BH2 adds to the carbon with the triple bond that has a partial negative charge. - Resulting structure: CCl3C=CH2. 2. **Oxidation**: - Replace BH2 with OH. - Resulting structure: CCl3C(OH)=CH2 (enol form). 3. **Tautomerization**: - Converts to CCl3C=O (a ketone). 4. **Conclusion**: This option yields a ketone. #### Option 4: CH3C≡CCH3 1. **Hydroboration**: - BH2 adds to the terminal carbon (less substituted), and H adds to the adjacent carbon. - Resulting structure: CH3C=CH2. 2. **Oxidation**: - Replace BH2 with OH. - Resulting structure: CH3C(OH)=CH2 (enol form). 3. **Tautomerization**: - Converts to CH3C=O (an aldehyde). 4. **Conclusion**: This option does not yield a ketone. ### Final Answer After analyzing all options, **Option 3 (CCl3C≡CH)** is the only compound that yields a ketone after hydroboration-oxidation.
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