`C_(2)H_(5)Br+CH_(3)-underset(CH_(3))underset(|)(CH)-Broverset((Na)dry ether)(to)'P'` (major)
Which is not product 'P'-

Options

A. `CH_(3)-CH_(2)-CH_(2)-CH_(3)`
B. `CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-CH_(3)`
C. `CH_(3)-underset(CH_(3))underset(|)(CH)-underset(CH_(3))underset(|)(CH)-CH_(3)`
D. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(3)`

Answer

To solve the problem, we need to analyze the reaction between ethyl bromide (C2H5Br) and the compound CH3-CH(CH3)-Br in the presence of sodium (Na) and dry ether, which is characteristic of the Wurtz reaction. The Wurtz reaction is used to couple alkyl halides to form symmetrical alkanes, but when unsymmetrical alkyl halides are involved, a mixture of products can be formed.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are ethyl bromide (C2H5Br) and a brominated compound (CH3-CH(CH3)-Br).

2. **Understand the Wurtz Reaction**:
The Wurtz reaction involves the coupling of two alkyl halides in the presence of sodium and dry ether, leading to the formation of alkanes. The general reaction can be represented as:
\[ 2 R-X + 2 Na \rightarrow R-R + 2 NaX \]
where R is an alkyl group and X is a halogen (Br in this case).

3. **Reactions of the Individual Alkyl Halides**:
- For C2H5Br:
\[ 2 C2H5Br + 2 Na \rightarrow C4H10 + 2 NaBr \]
- For CH3-CH(CH3)-Br:
\[ 2 (CH3-CH(CH3)-Br) + 2 Na \rightarrow C6H14 + 2 NaBr \]

4. **Possible Products**:
- From C2H5Br, we can form butane (C4H10).
- From CH3-CH(CH3)-Br, we can form hexane (C6H14).
- When both reactants are mixed, they can also couple to form a new product:
\[ C2H5 + CH3-CH(CH3) \rightarrow C5H12 \]
This product is likely to be 2-pentane.

5. **Identify the Major Products**:
The major products formed from the reaction will be:
- Butane (C4H10)
- Hexane (C6H14)
- 2-Pentane (C5H12)

6. **Determine Which is Not a Product**:
The question asks for which compound is NOT a product 'P'. Given the possible products identified, we need to check against the options provided in the question.

### Conclusion:
Based on the analysis, the products formed from the reaction include butane, hexane, and 2-pentane. Any other compound not listed among these would be the answer to the question.