`CH_(4)+H_(2)Ooverset(Ni)underset(1273K)(to)'P'` Product 'P' is -

Options

A. water gas
B. Producer gas
C. Synthesis gas
D. Natural gas

Answer

To solve the problem, we need to analyze the reaction between methane (CH₄) and water (H₂O) in the presence of a nickel catalyst at a high temperature of 1273 K.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are methane (CH₄) and water (H₂O). Methane is a hydrocarbon, and water is in the form of steam in this reaction.

2. **Understand the Role of the Catalyst**: Nickel (Ni) is used as a catalyst in this reaction. A catalyst is a substance that speeds up a chemical reaction without being consumed in the process.

3. **Determine the Reaction Conditions**: The reaction occurs at a high temperature of 1273 K. High temperatures typically favor reactions that produce gases and can lead to the breakdown of reactants into simpler products.

4. **Write the Balanced Reaction**: The reaction between methane and steam can be represented as follows:
\[ CH₄ + H₂O \overset{Ni}{\rightarrow} CO + 3H₂ \]
This indicates that one molecule of methane reacts with one molecule of steam to produce one molecule of carbon monoxide (CO) and three molecules of hydrogen gas (H₂).

5. **Identify the Product**: The product 'P' in this reaction is carbon monoxide (CO) and hydrogen gas (H₂). Together, they are often referred to as synthesis gas or syngas.

6. **Conclusion**: Therefore, the product 'P' formed from the reaction of methane and steam in the presence of nickel at 1273 K is carbon monoxide (CO) and hydrogen gas (H₂).

### Final Answer:
The product 'P' is carbon monoxide (CO) and hydrogen gas (H₂), commonly known as synthesis gas or syngas.

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