The product of the reaction is `CH_(3)-CH_(2)-overset(O)overset(||)(C)-OAgoverset(Br_(2))underset(Delta)(to)` Major product

Options

A. `CH_(2)=CH_(2)`
B. `CH_(3)-CH_(2)-Br`
C. `CH_(3)CH_(2)CH_(2)-Br`
D. `CH_(3)-CH=CH-CH_(3)`

Answer

To solve the question regarding the major product of the reaction involving `CH3-CH2-C(=O)-OAg` with `Br2` under heating, we will follow these steps:

### Step 1: Identify the Reactants
The reactant is a silver salt of a carboxylic acid, specifically `CH3-CH2-C(=O)-OAg`. This indicates that we have an ethyl group attached to a carbonyl (C=O) and a silver salt of the carboxylic acid.

**Hint:** Look for the functional groups present in the reactant to understand the type of reaction that may occur.

### Step 2: Recognize the Reaction Type
When a silver salt of a carboxylic acid reacts with bromine (Br2) and is heated, it typically undergoes a reaction known as the **Hunsdiecker reaction**. This reaction involves the decarboxylation of the carboxylic acid derivative.

**Hint:** Recall that decarboxylation involves the removal of carbon dioxide (CO2) from the compound.

### Step 3: Reaction Mechanism
1. The silver salt reacts with Br2, leading to the formation of a bromo compound.
2. The decarboxylation process occurs, which involves the loss of CO2.

The overall reaction can be summarized as:
- `CH3-CH2-C(=O)-OAg + Br2 → CH3-CH2Br + CO2 + AgBr`

**Hint:** Pay attention to the products formed during the reaction, especially the gaseous CO2.

### Step 4: Identify the Major Product
After the decarboxylation and bromination, the major product formed is `CH3-CH2Br`, which is bromoethane. Additionally, byproducts such as CO2 and AgBr are also formed.

**Hint:** The major product is typically the most stable and abundant compound formed in the reaction.

### Conclusion
The major product of the reaction `CH3-CH2-C(=O)-OAg` with `Br2` under heating is `CH3-CH2Br` (bromoethane).

**Final Answer:** The major product is **bromoethane (CH3-CH2Br)**.