In the given reaction
`CH_(3)-CH=CH-CH_(2)-OHoverset(PC C)(to)` Product
Product is :

Options

A. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH`
B. `CH_(3)-CH_(2)-CH_(2)-CHO`
C. `CH_(3)-CH=CH-CHO`
D. `CH_(3)-CH=CH-COOH`

Answer

To solve the given reaction involving the compound `CH3-CH=CH-CH2-OH` with the reagent PCC (Pyridinium chlorochromate), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant and Reagent:**
- The reactant is `CH3-CH=CH-CH2-OH`, which is a 1-degree alcohol.
- The reagent is PCC (Pyridinium chlorochromate), which is used for the oxidation of alcohols.

2. **Understand the Function of PCC:**
- PCC is a mild oxidizing agent that selectively oxidizes primary alcohols to aldehydes without further oxidation to carboxylic acids.

3. **Determine the Structure of the Reactant:**
- The structure of the reactant can be drawn as follows:
```
CH3-CH=CH-CH2-OH
```
- Here, the `-OH` group indicates that it is a primary alcohol.

4. **Apply the Oxidation Reaction:**
- When the primary alcohol (`-CH2-OH`) is treated with PCC, it will be oxidized to an aldehyde (`-CHO`).
- The double bond in the compound remains unaffected during this oxidation.

5. **Write the Product:**
- The product after oxidation will be:
```
CH3-CH=CH-CHO
```
- This indicates that the `-OH` group has been converted to a `-CHO` group, resulting in the formation of an aldehyde.

6. **Final Product Confirmation:**
- The final product is `CH3-CH=CH-CHO`, which is an unsaturated aldehyde.

### Conclusion:
The product of the reaction `CH3-CH=CH-CH2-OH` with PCC is `CH3-CH=CH-CHO`.