Alcohol is not formed as product in

Options

A. `CH_(3)-CH_(2)-NH_(2)overset(NaNO_2+HCl(aq))(to)`
B. `CH_(3)-CHOunderset((ii)H_(2)O)overset((i)CH_(3)-MgBr)(to)`
C. `H_(3)C-overset(O)overset(||)(C)-NH_(2)overset(LiAlH_(4))(to)`
D. `CH_(3)-CH_(2)-Cloverset(KOH(aq))(to)`

Answer

To determine in which reaction alcohol is not formed as a product, we will analyze each of the four given reactions step by step.

### Step 1: Analyze the first reaction
**Reaction:** CH3CH2NH2 + NaNO2 + HCl

- **Process:**
- CH3CH2NH2 (ethylamine) reacts with sodium nitrite (NaNO2) in the presence of hydrochloric acid (HCl) to form nitrous acid (HONO).
- The reaction leads to the formation of ethanol (CH3CH2OH) and nitrogen gas (N2) along with water (H2O).

- **Conclusion:** Alcohol (ethanol) is formed in this reaction.

### Step 2: Analyze the second reaction
**Reaction:** CH3CHO + CH3MgBr + H2O

- **Process:**
- CH3CHO (acetaldehyde) reacts with methylmagnesium bromide (CH3MgBr) in dry ether, leading to the formation of a Grignard addition product.
- When water (H2O) is added, the Grignard reagent reacts to form a secondary alcohol (CH3CH(OH)CH3).

- **Conclusion:** Alcohol (a secondary alcohol) is formed in this reaction.

### Step 3: Analyze the third reaction
**Reaction:** CH3CONH2 + LiAlH4

- **Process:**
- CH3CONH2 (acetamide) is treated with lithium aluminium hydride (LiAlH4), a strong reducing agent.
- This reaction reduces the amide to a primary amine (CH3NH2) without forming any alcohol.

- **Conclusion:** No alcohol is formed in this reaction.

### Step 4: Analyze the fourth reaction
**Reaction:** CH3CH2Cl + KOH (aqueous)

- **Process:**
- CH3CH2Cl (ethyl chloride) reacts with aqueous KOH, leading to the formation of ethanol (CH3CH2OH) and potassium chloride (KCl).

- **Conclusion:** Alcohol (ethanol) is formed in this reaction.

### Final Answer
Based on the analysis of all four reactions, the reaction in which alcohol is not formed is:
**Option 3: CH3CONH2 + LiAlH4**