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Order of boiling points is- underset(...

Order of boiling points is-
`underset((a))("Pentan"-1-ol), underset((b))(n-"butane"),underset((c))("Pentanal"),underset((d))("ethoxyethane")`

A

`bgtdgtcgta`

B

`agtcgtdgtb`

C

`cgtdgtbgta`

D

`dgtagtbgtc`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of boiling points for the given compounds: Pentan-1-ol (a), n-butane (b), Pentanal (c), and ethoxyethane (d), we will analyze the intermolecular forces and molecular weights of each compound. ### Step-by-Step Solution: 1. **Identify the Compounds and Their Structures**: - **Pentan-1-ol (a)**: This is an alcohol with the structure CH3-CH2-CH2-CH2-CH2-OH. It has a hydroxyl (-OH) group, which allows for hydrogen bonding. - **n-butane (b)**: This is an alkane with the structure CH3-CH2-CH2-CH3. It has only van der Waals forces (dispersion forces) acting between molecules. - **Pentanal (c)**: This is an aldehyde with the structure CH3-CH2-CH2-CH2-CHO. It has a carbonyl (C=O) group, which can participate in dipole-dipole interactions but does not form hydrogen bonds. - **Ethoxyethane (d)**: Also known as ethyl ether, its structure is CH3-CH2-O-CH2-CH3. It has an ether functional group, which primarily exhibits van der Waals forces. 2. **Analyze Intermolecular Forces**: - **Pentan-1-ol (a)**: Exhibits strong hydrogen bonding due to the -OH group, leading to a higher boiling point. - **n-butane (b)**: Exhibits only weak van der Waals forces, leading to a lower boiling point. - **Pentanal (c)**: Exhibits dipole-dipole interactions but no hydrogen bonding, leading to a moderate boiling point. - **Ethoxyethane (d)**: Exhibits weak van der Waals forces, similar to n-butane, but slightly higher due to its larger size. 3. **Estimate Boiling Points Based on Intermolecular Forces**: - Pentan-1-ol (a) will have the highest boiling point due to hydrogen bonding. - Pentanal (c) will have a higher boiling point than ethoxyethane (d) due to dipole-dipole interactions. - Ethoxyethane (d) will have a higher boiling point than n-butane (b) due to its larger molecular size, despite both having weak van der Waals forces. 4. **Order the Compounds by Boiling Point**: - Based on the analysis: - Highest boiling point: Pentan-1-ol (a) - Next: Pentanal (c) - Next: Ethoxyethane (d) - Lowest boiling point: n-butane (b) 5. **Final Order of Boiling Points**: - The correct order of boiling points is: - **Pentan-1-ol (a) > Pentanal (c) > Ethoxyethane (d) > n-butane (b)** ### Final Answer: The order of boiling points is: **a > c > d > b**.
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