`CH_(3)-Br+NaO-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(3)to` ?
The product is

Options

A. `CH_(3)-O-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(3)`
B. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(2))overset(||)(C)`
C. `CH_(2)=CH_(2)`
D. `CH_(3)-O-underset(CH_(3))underset(|)(CH)-CH_(3)`

Answer

To solve the given question, we need to analyze the reaction between CH₃Br (methyl bromide) and the sodium alkoxide (NaO-CH₃) derived from the tertiary alcohol. This reaction is an example of the Williamson ether synthesis.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are CH₃Br (methyl bromide) and NaO-CH₃ (sodium methoxide).

2. **Understand the Reaction Type**:
- This reaction is a Williamson ether synthesis, which involves the formation of an ether from an alkyl halide and an alkoxide.

3. **Mechanism of Reaction**:
- The sodium alkoxide (NaO-CH₃) has a negatively charged oxygen atom (O⁻) which acts as a nucleophile.
- The carbon attached to the bromine in CH₃Br has a partial positive charge due to the electronegativity of bromine, making it susceptible to nucleophilic attack.

4. **Nucleophilic Attack**:
- The negatively charged oxygen (O⁻) from the sodium alkoxide attacks the carbon atom of CH₃Br, displacing the bromine atom (Br⁻).
- This is an SN2 reaction, where the nucleophile attacks from the opposite side of the leaving group (Br).

5. **Formation of Ether**:
- After the nucleophilic attack, the product formed is an ether (CH₃-O-CH₃) and sodium bromide (NaBr) as a byproduct.

6. **Final Product**:
- The final product of the reaction is dimethyl ether (CH₃-O-CH₃) and NaBr.

### Conclusion:
The product of the reaction CH₃Br + NaO-CH₃ is dimethyl ether (CH₃-O-CH₃) along with NaBr as a byproduct.