Which of the following does not react with
`(I_(2)+NaOH)` or NaOI :

Options

A. `CH_(3)-CHO`
B. `CH_(3)-CH_(2)-CHO`
C. `CH_(3)-CH_(2)-OH`
D. `CH_(3)-underset(O)underset(||)C-CH_(3)`

Answer

To determine which of the following compounds does not react with \( I_2 + NaOH \) or \( NaOI \), we need to analyze the reactivity of different organic compounds, particularly aldehydes, ketones, and alcohols, with these reagents.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
The reaction of \( I_2 + NaOH \) is commonly used in the iodoform test, which identifies methyl ketones and certain aldehydes. The presence of the \( CH_3CO \) (methyl ketone) group is crucial for the reaction to occur.

2. **Identifying the Functional Groups**:
- Aldehydes and ketones that have the \( CH_3CO \) group will react.
- Alcohols can also react if they can be oxidized to form an aldehyde or ketone that contains the \( CH_3CO \) group.

3. **Analyzing the Given Compounds**:
- **Compound 1**: \( CH_3CHO \) (Acetaldehyde)
- This compound contains the \( CH_3CO \) group and will react with \( I_2 + NaOH \).
- **Compound 2**: \( CH_3CH_2C(=O)CH_3 \) (Butan-2-one)
- This compound also contains the \( CH_3CO \) group and will react with \( I_2 + NaOH \).
- **Compound 3**: \( CH_3CH_2OH \) (Ethanol)
- Ethanol does not have the \( CH_3CO \) group. It is an alcohol and will not react in the iodoform test.
- **Compound 4**: \( CH_3C(=O)CH_3 \) (Acetone)
- This compound contains the \( CH_3CO \) group and will react with \( I_2 + NaOH \).

4. **Conclusion**:
The compound that does not react with \( I_2 + NaOH \) is **Compound 3: Ethanol (CH3CH2OH)**.

### Final Answer:
**Ethanol (CH3CH2OH)** does not react with \( I_2 + NaOH \) or \( NaOI \).

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