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CH(3)-CH=CH-underset(O)underset(||)(C)-C...

`CH_(3)-CH=CH-underset(O)underset(||)(C)-CH_(3)+NH_(2)-OHoverset(H^(o+))(to)` major product is

A

`CH_(3)-underset(NH_(2))underset(|)(CH)-underset(OH)underset(|)(CH)-underset(O)underset(||)(C)-CH_(3)`

B

`CH_(3)-underset(OH)underset(|)(CH)-underset(NH_(2))underset(|)(CH)-underset(O)underset(||)(C)-CH_(3)`

C

`CH_(3)-CH=CH-underset(CH_(3))underset(|)(C)=N-OH`

D

`CH_(2)-underset(OH)underset(|)(CH)-CH_(2)-underset(O)underset(||)(C)-CH_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question, we need to determine the major product formed when hydroxylamine (NH2OH) reacts with the provided ketone. The ketone structure is CH3-CH=CH(C=O)-CH3. ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactants are a ketone (CH3-CH=CH(C=O)-CH3) and hydroxylamine (NH2OH). 2. **Understand the Reaction Type**: The reaction between a ketone and hydroxylamine is an addition reaction, where the carbonyl group (C=O) of the ketone reacts with hydroxylamine. 3. **Draw the Structure of the Ketone**: The ketone can be represented as follows: ``` CH3 | CH3-CH=CH-C=O ``` 4. **Add Hydroxylamine to the Ketone**: Hydroxylamine will attack the carbonyl carbon (C=O) of the ketone. The nitrogen from hydroxylamine will form a bond with the carbonyl carbon, and the oxygen will take a hydrogen from the nitrogen, leading to the formation of a double bond between carbon and nitrogen. 5. **Form the Intermediate Product**: The reaction will produce an intermediate compound where the carbonyl oxygen is replaced by the nitrogen from hydroxylamine: ``` CH3 | CH3-CH=CH-C=N-OH ``` 6. **Elimination of Water**: During the reaction, a water molecule (H2O) is eliminated. The hydroxyl group (OH) from hydroxylamine and a hydrogen from the carbonyl carbon combine to form water. 7. **Final Product Structure**: The final product will be a double bond between the carbon and nitrogen, resulting in: ``` CH3 | CH3-CH=CH-C=N-OH ``` 8. **Identify the Major Product**: The major product formed from this reaction is the oxime of the ketone, which is represented as: ``` CH3 | CH3-CH=CH-C=N-OH ``` 9. **Conclusion**: The major product of the reaction between the given ketone and hydroxylamine is the corresponding oxime, which matches with option number C. ### Final Answer: The major product is **option C**.
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Knowledge Check

  • CH_(3)CH_(2)-overset(O)overset(||)(C)-CH_(3)underset(HCl)overset(NaNO_(2))to , Major product of this reaction is :

    A
    `CH_(3)underset(NO)underset(|)(C)H-overset(O)overset(||)(C)-CH_(3)`
    B
    `CH_(3)-CH_(2)-overset(O)overset(||)(C)-CH=N-OH`
    C
    D
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