`H_(3)C-COOHunderset(Delta)overset(P_(2)O_(5))(to)Aoverset(PCl_(5))(to)Bunderset(AlCl_(3))overset(C_(6)H_(6))(to)C,` C is-

Options

A.
B.
C.
D.

Answer

To solve the question step by step, we will analyze each reaction mentioned in the problem.

### Step 1: Reaction of Acetic Acid with P2O5
- **Starting Material**: Acetic Acid (H₃C-COOH)
- **Reagent**: P₂O₅ (Phosphorus Pentoxide)
- **Process**: P₂O₅ is a dehydrating agent, which means it removes water from the acetic acid.
- **Product A**: When acetic acid is treated with P₂O₅ and heated, it loses a water molecule and forms **Acetic Anhydride** (CH₃C(O)OC(O)CH₃).

### Step 2: Reaction of Product A with PCl5
- **Starting Material**: Acetic Anhydride (Product A)
- **Reagent**: PCl₅ (Phosphorus Pentachloride)
- **Process**: PCl₅ reacts with acetic anhydride to convert it into acetyl chloride.
- **Product B**: The reaction produces **2 moles of Acetyl Chloride** (CH₃C(O)Cl).

### Step 3: Reaction of Product B with Benzene and AlCl3
- **Starting Material**: Acetyl Chloride (Product B)
- **Reagents**: Benzene (C₆H₆) and AlCl₃ (Aluminum Chloride, a Lewis acid)
- **Process**: The acetyl chloride undergoes Friedel-Crafts acylation with benzene in the presence of AlCl₃, leading to the formation of acetophenone.
- **Product C**: The final product is **Acetophenone** (CH₃C(O)C₆H₅).

### Final Answer
Thus, the final product C is **Acetophenone**.

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