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Which of the following have maximum valu...

Which of the following have maximum value of `pK_(b)` in Aqueous phase-

A

N-Methyl aniline

B

N,N-di ethyl ethanamine

C

Benzenamine

D

Phenyl methanamine

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds has the maximum value of \( pK_b \) in the aqueous phase, we need to analyze the basicity of each compound. The \( pK_b \) value is inversely related to the base strength; a higher \( pK_b \) indicates a weaker base. Here’s a step-by-step solution: ### Step 1: Understand the Concept of Basicity - Basicity is the ability of a compound to accept protons (H⁺ ions). The stronger the base, the more readily it accepts protons, resulting in a lower \( pK_b \) value. - Conversely, a weaker base will have a higher \( pK_b \) value. ### Step 2: Identify the Compounds The compounds given are: 1. N-methyl aniline 2. Diethylamine 3. Aniline (Benzamine) 4. Phenylmethanamine ### Step 3: Analyze Each Compound 1. **N-methyl aniline**: The methyl group is an electron-donating group, which increases the electron density on the nitrogen, enhancing its basicity. 2. **Diethylamine**: Similar to N-methyl aniline, the ethyl groups are also electron-donating, making this compound a strong base. 3. **Aniline (Benzamine)**: The amino group (-NH₂) is attached to a benzene ring. The lone pair on nitrogen can participate in resonance with the benzene ring, reducing its availability to accept protons and thus decreasing its basicity. 4. **Phenylmethanamine**: This compound has a methanamine group (-NH₂) connected to a phenyl group. The resonance effect of the phenyl group will also decrease the basicity of the nitrogen atom. ### Step 4: Compare Basicity - **N-methyl aniline** and **diethylamine** are stronger bases due to the electron-donating effects of their alkyl groups. - **Aniline** has reduced basicity because of resonance stabilization, which lowers the availability of the lone pair on nitrogen. - **Phenylmethanamine** is similar to aniline in terms of resonance effects, but the basicity is slightly lower due to the additional methylene group. ### Step 5: Determine the Weakest Base Among the four compounds, **aniline** has the weakest basicity due to the resonance effect that stabilizes the lone pair on nitrogen, making it less available for protonation. Therefore, it will have the highest \( pK_b \) value. ### Conclusion The compound with the maximum value of \( pK_b \) in the aqueous phase is **Aniline (Benzamine)**.
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