Which of the following gives paracetamol on acetlylation ?

Options

A.
B.
C.
D.

Answer

To determine which compound gives paracetamol upon acetylation, we can follow these steps:

### Step 1: Understand the Structure of Paracetamol
Paracetamol (acetaminophen) has the following structure:
- It contains a hydroxyl group (-OH) and an amine group (-NH2) on a benzene ring.
- The amine group is in the para position relative to the hydroxyl group.

### Step 2: Identify the Reaction of Acetylation
Acetylation involves the introduction of an acetyl group (CH3CO-) to a compound. In the case of paracetamol, the amine group (-NH2) can react with acetic anhydride or acetyl chloride to form the acetylated product.

### Step 3: Write the Reaction
The reaction can be represented as follows:
- Starting compound: Aniline (C6H5NH2) or another suitable amine.
- Reagent: Acetic anhydride (or acetyl chloride).
- The reaction will yield paracetamol:
\[ C_6H_5NH_2 + CH_3COOH \rightarrow C_6H_5NHCOCH_3 + H_2O \]

### Step 4: Analyze the Given Options
To find out which compound gives paracetamol upon acetylation, we need to check the position of the amine group (-NH2) in the provided options:
- If the amine group is in the para position relative to the hydroxyl group, it can produce paracetamol upon acetylation.
- If the amine group is in the meta or ortho position, it will not yield paracetamol.

### Step 5: Conclusion
After analyzing the options, the correct answer is the compound where the amine group is at the para position relative to the hydroxyl group.

### Final Answer
The correct option that gives paracetamol upon acetylation is the one with the amine group at the para position.

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