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In Kjeldahl's method used for estimation...

In Kjeldahl's method used for estimation of nitrogen, ammonia evolved from 0.6g of ml sample of organic compound neutralised 20 ml of 1 N `H_(2)SO_(4)`. Then calculate % of nitrogen in that compound :

A

`37.33`

B

`46.67`

C

`45.77`

D

`43.33`

Text Solution

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The correct Answer is:
To calculate the percentage of nitrogen in the organic compound using Kjeldahl's method, we can follow these steps: ### Step 1: Understand the formula for calculating the percentage of nitrogen. The formula to calculate the percentage of nitrogen (N) in the sample is given by: \[ \% N = \frac{1.4 \times N \times V}{m} \] Where: - \( N \) = Normality of \( H_2SO_4 \) - \( V \) = Volume of \( H_2SO_4 \) used (in mL) - \( m \) = Mass of the organic compound sample (in grams) ### Step 2: Identify the values from the problem. From the problem statement: - Mass of the organic compound sample, \( m = 0.6 \, \text{g} \) - Normality of \( H_2SO_4, N = 1 \, \text{N} \) - Volume of \( H_2SO_4, V = 20 \, \text{mL} \) ### Step 3: Substitute the values into the formula. Now, we can substitute the values into the formula: \[ \% N = \frac{1.4 \times 1 \times 20}{0.6} \] ### Step 4: Perform the calculations. Calculating the numerator: \[ 1.4 \times 1 \times 20 = 28 \] Now, divide by the mass of the sample: \[ \% N = \frac{28}{0.6} = 46.67 \] ### Step 5: State the final answer. The percentage of nitrogen in the organic compound is: \[ \% N = 46.67\% \]
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