A hammer of mass 1kg moving with a speed of `6 ms^(-1)` strikes a wall and comes to rest in 0.1 s. Calculate,
(i) impulse of the force
(ii) Average retarding force that stops the hammer.
(iii) Average retardation of the hammer.

Explanation

Impulse `=Fxxt=m(v-u)=1(0-6)=-6Ns`
Average retarding force that stops the hammer `F=("Impulse")/("time")=(6)/(0.1)=60N`
and average retardation `a=(F)/(m)=(60)/(1)=60ms^(-2)`