A `20 kg` monkey has a firm hold on a light rope that passes over a frictionless pulley and is attached to a `20 kg` bunch of bananas. The monkey looks upwards , sees the bananas and starts to climb the rope to get them.
(a) As the monkey climbs ,do the bananas move up , move down or remain at rest?
(b) As the monkey climbs ,does the distance between the monkey and the banana decrease, increase or remain same?
(c) The monkey releases her hold on the rope .What happens to the distance between the monkey and the bananas while she is falling ?
(d) Before reaching the ground , the monkey grabs the rope to stop her fall. What will happen to bananas ?

Explanation

As monkey is lifint upward so effective weight of monkey `W_(m)=M_(m)(g+a)`
As per given condition `W_(m)=W_(b)rArrM_(m)(g+a)=M_(b)g`
`rArra=((M_(b)-M_(m))g)/(M_(m))=((16-12)/(12))xx9.8=(9.8)/(3)=3.26 m//s^(2)`