A particle moves in the x - y plane under the action of a force F such that the coordinates of its linear momentum `vecP` at any time t is `p_(x)=2 cost, p_(y)=2 sin t`
The angel `theta` between `vecF and vecP` at a given that time t will be

Explanation

Momentum of the body `vecP=2cos thati+2sinthatj`
So force on the body is `vecF=(dvecp)/(dt)=-2sin t hati_2cos thatj`
If angle between `vecF` and `becp` is `theta` then
`costheta=(vecF.vecp)/(Fp)=(-4cos t sin t+4cos t sin t)/(Fp)=0` so `theta=90^(@)`