Velocity of particle of mass 2kg varies with time t accoridng to the equation `vecv=(2thati+4hatj)ms^(-1)`. Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s.

Explanation

To find the impulse imparted to the particle in the time interval from \( t = 0 \) to \( t = 2 \) seconds, we can follow these steps:

### Step 1: Determine the velocity at \( t = 0 \) and \( t = 2 \)

The velocity of the particle is given by the equation:
\[ \vec{v} = (2t \hat{i} + 4 \hat{j}) \, \text{m/s} \]
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