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A block of mass kg lies on a horizontal surface in a truck· The coefficient of stalk friction between the block and the surface is 0.6. If the acceleration of the truck is `5ms^(-2)`. The frictional force acting on the block is

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Fictitious force on the block `F=ma=1xx5=5N`
While the limiting friction force
`F=mu_(s)N=mu_(s)mg=0.6xx1xx9.8=5.88N`
As applied force F lesser than limiting friciton force. The block will remain at rest in the truck and the force of friction will be equal to 5N and in the direction of accelration of the truck.
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