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Three blocks of messes `m_1,m_2 and m_3` are connected to a massless staring on a frictionless table as shown in the figure. They are pulled with a force of 40 N. Of `m_1 = 10 kg , m_2 = 6 kg and m_3 = 4 kg` ,then tension `T_2` will be

A

10N

B

20N

C

32N

D

40N

Text Solution

Verified by Experts

The correct Answer is:
C

The common acceleration of the blocks is
`a (40)/(10+6+4)=(40)/(20)=2 m//s^(2)`
`therefore` Tension `T_(2)=(m_(1)+m_(2))a=(10+6)2`
`=12xx2=32N`.
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