A 5kg mass is accelerated from rest to 60 m/s in 1 sec. what force acts on it:

Options

A. `5xx60N`
B. `(5//60)xx981N`
C. `60^(2)xx52N`
D. `(5/2)xx60^(2)xx981N`

Explanation

To solve the problem step by step, we will follow the principles of Newton's laws of motion.

### Step 1: Identify the given information
- Mass (m) = 5 kg
- Initial velocity (u) = 0 m/s (since it starts from rest)
- Final velocity (v) = 60 m/s
- Time (t) = 1 s

### Step 2: Use the equation of motion to find acceleration
We can use the equation of motion:
\[ v = u + at \]
Where:
- \( v \) = final velocity
- \( u \) = initial velocity
- \( a \) = acceleration
- \( t \) = time

Substituting the known values into the equation:
\[ 60 = 0 + a \cdot 1 \]
This simplifies to:
\[ 60 = a \]
Thus, the acceleration \( a \) is:
\[ a = 60 \, \text{m/s}^2 \]

### Step 3: Calculate the force using Newton's second law
According to Newton's second law, the force (F) acting on an object is given by:
\[ F = m \cdot a \]
Substituting the values we have:
\[ F = 5 \, \text{kg} \cdot 60 \, \text{m/s}^2 \]
Calculating this gives:
\[ F = 300 \, \text{N} \]

### Final Answer:
The force acting on the mass is **300 N**.

---