The rear side of a truck is open and a box of mass 20kg is placed on the truck 4m away from the open end, m = 0.15 and `g= 10 //sec^(2)`. The truck starts from rest with an acceleration of `2 m//sec^(2)` on a straight road. The distance moved by the truck when box starts fall down is `:`

Options

A. 4m
B. 8m
C. 16m
D. 32m

Answer

C

Explanation

`a_(r)=(20xx2-20xx10xx0.5)/(20)=0.5m//s^(2)`
`therefore 4=(1)/(2)xx0.5xxt^(2) t=4s`
`therefore` distance of truck `=(1)/(2)xx2xx4xx4=16m`