The mechanical advantage of a wheel axle is 5 what will be thereforce required to lift a 200kg wt?

Options

A. 10kg wt.
B. 2 kg wt.
C. 20 kg wt.
D. 40 kg wt.

Explanation

To solve the problem of finding the force required to lift a 200 kg weight using a wheel axle with a mechanical advantage of 5, we can follow these steps:

### Step 1: Understand the Concept of Mechanical Advantage
Mechanical Advantage (MA) is defined as the ratio of the output force (load) to the input force (effort). It can be expressed mathematically as:
\[ \text{MA} = \frac{\text{Output Force}}{\text{Input Force}} \]

### Step 2: Identify the Given Values
From the problem, we know:
- Mechanical Advantage (MA) = 5
- Output Force (Weight to be lifted) = 200 kg

### Step 3: Rearrange the Formula to Find Input Force
We can rearrange the formula to find the Input Force (Effort):
\[ \text{Input Force} = \frac{\text{Output Force}}{\text{MA}} \]

### Step 4: Substitute the Known Values
Now, we can substitute the known values into the rearranged formula:
\[ \text{Input Force} = \frac{200 \text{ kg}}{5} \]

### Step 5: Calculate the Input Force
Now, perform the calculation:
\[ \text{Input Force} = \frac{200}{5} = 40 \text{ kg} \]

### Step 6: Conclusion
The force required to lift the 200 kg weight using the wheel axle is 40 kg.

### Final Answer
The required force is 40 kg.

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