A body of mass 100g is sliding on a inclined plane with an inclination of `60^(@)`. What is the frictional force experienced, if coeficient of friction is 1.7? (Take `g=10m//s^(2)`)

Options

A. 0.85N
B. 0.95N
C. 1.05N
D. 1.145N

Explanation

To solve the problem of finding the frictional force experienced by a body sliding on an inclined plane, we can follow these steps:

### Step 1: Identify the given values
- Mass of the body (m) = 100 g = 0.1 kg (conversion from grams to kilograms)
- Angle of inclination (θ) = 60°
- Coefficient of friction (μ) = 1.7
- Acceleration due to gravity (g) = 10 m/s²

### Step 2: Calculate the weight of the body
The weight (W) of the body can be calculated using the formula:
\[ W = m \cdot g \]
Substituting the values:
\[ W = 0.1 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 1 \, \text{N} \]

### Step 3: Resolve the weight into components
The weight of the body can be resolved into two components:
- Perpendicular to the inclined plane: \( W_{\perpendicular} = W \cdot \cos(θ) \)
- Parallel to the inclined plane: \( W_{\parallel} = W \cdot \sin(θ) \)

Calculating these components:
- \( W_{\perpendicular} = 1 \, \text{N} \cdot \cos(60°) = 1 \, \text{N} \cdot \frac{1}{2} = 0.5 \, \text{N} \)
- \( W_{\parallel} = 1 \, \text{N} \cdot \sin(60°) = 1 \, \text{N} \cdot \frac{\sqrt{3}}{2} \approx 0.866 \, \text{N} \)

### Step 4: Calculate the normal force
The normal force (N) acting on the body is equal to the perpendicular component of the weight:
\[ N = W_{\perpendicular} = 0.5 \, \text{N} \]

### Step 5: Calculate the frictional force
The frictional force (F) can be calculated using the formula:
\[ F = \mu \cdot N \]
Substituting the values:
\[ F = 1.7 \cdot 0.5 \, \text{N} = 0.85 \, \text{N} \]

### Conclusion
The frictional force experienced by the body is **0.85 N**.

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