If acceleration of `A` is `2m//s^(2)` to left and acceleration of `B` is `1m//s^(2)` to left, then acceleration of `C` is-

Options

A. `1 m//s^(2)` downwards
B. `1 m//s^(2)` upwards
C. `2 m//s^(2)` downwards
D. `2 m//s^(2)` upwards

Answer

B

Explanation

`l_(1)+l_(2)+l_(3)+l_(4)+l_(5)=` constant
`rArr l_(1)+l_(2)+l_(3)+l_(4)+l_(5)=0`
`rArra_(C)+a_(A)+(a_(A)-a_(B))+(-a_(B))+a_(C)=0`
`rAa 2a_(C)+2a_(A)-2a_(B)=0`
`rArr a_(C)=a_(B)-a_(A)=1-2=-1ms^(-2)` upwards