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Two particles A and B performing SHM alo...

Two particles `A` and `B` performing `SHM` along `x` and `y-`axis respectively with equal amplitude and frequency of `2 cm` and `1 Hz` respectively. Equilibrium positions of the particles `A` and `B` are at the co-ordinates `(3, 0)` and `(0, 4)` respectively. At `t = 0, B` is at its equilibrium positions and moving towards the origin, while `A` is nearest to the origin and moving away from the origin. If the maximum and minimum distances between `A` and `B` is `s_(1)` and `s_(2)` then find `s_(1) + s_(2)` (in `cm`).

A

`x = (2 cm) cos 2pit`

B

`x = (3 cm) - (2 cm) cos 2 pit`

C

`x = (2 cm) sin 2 pit`

D

`x = (3 cm) - (2 cm) sin 2pit`

Text Solution

Verified by Experts

The correct Answer is:
B
As A is at its negative extreme at `t = 0`
so `x - 3 = 2 sin (2pit + 3pi//2) rArr x = 3-2 cos (2pit)`
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