If a simple harmonic motion is represented by `(d^(2)x)/(dt^(2))+alphax=0`, its time period is

Options

A. `(2pi)/(alpha)`
B. `(2pi)/(sqrt(alpha))`
C. `2pialpha`
D. `2pisqrt(alpha)`

Answer

B

Explanation

`(d^(2)x)/(dt^(2)) + alphax = 0`
On comparing the above equation with the equation of SHM
`(d^(2)x)/(dt^(2)) + omega^(2)x = 0 rArr omega^(2) = a rArr omega =sqrt(alpha) rArr T = (2pi)/(sqrt(alpha))`