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Starting from origin at , a body oscilla...

Starting from origin at , a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75 % of the total energy?

A

`1/6s`

B

`1/4s`

C

`1/3s`

D

`1/12s`

Text Solution

Verified by Experts

The correct Answer is:
A
`KE = (75/100)TE`
`rArr 1/2momega^(2)(A^(2) - x^(2)) = 3/4[1/2momega^(2)A^(2)] rArr x = (A)/(2)`
Now from `x = Asinomegat` we have
`A/2 = Asin(omegat) rArr ((2pi)/(T)) t = (pi)/(6) rArr t = 1/6s`
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