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the period of oscillation of a simple pe...

the period of oscillation of a simple pendulum of length `L` suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination `prop`, is given by.

A

`2pisqrt((L)/(gcosalpha))`

B

`2pisqrt((L)/(gsinalpha))`

C

`2pisqrt((L)/(g))`

D

`2pisqrt((L)/(g tanalpha))`

Text Solution

Verified by Experts

The correct Answer is:
A
Free body diagram of bob of the pendulum with respect to the accelerating frame of reference is as follows :

`:.` Net force on the bob is
`F_("net") = mg cos alpha` (figure b)
or
Net acclerating of the bob is
`g_(eff) = g cos alpha`
`T = 2pisqrt((L)/(g_(eff)))`
`rArr t = 2pisqrt((L)/(gcosalpha))`
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