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A proton and an alpha-particle are accel...

A proton and an `alpha`-particle are accelerated through the same potential difference. The ratio of Broglie wavelength `lamda_(p)` to that of `lamda_(alpha)` is

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`lambda = (h)/(mv) = (h)/(sqrt(2mE)) = (h)/(sqrt(2mqV)) [:' E = qV]` , for proton `m_(p) = m, q = e`
for `alpha`- particle `m_(alpha) = 4m, e = 2e, (lambda_(alpha))/(lambda_(p)) sqrt((m_(p)q_(p))/(m_(alpha)q_(alpha))) = 1/(2sqrt(2))`
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