`.^(40)K` is an unusual isotope, in that it decays by negative beta emission, positive beta emission, and electron capture. Find the Q values for these decays.

Explanation

To find the Q values for the decays of the unusual isotope \(^{40}K\) (Potassium-40), we will analyze three types of decay: negative beta emission, positive beta emission, and electron capture. The Q value represents the energy released during the decay process.

### Step-by-Step Solution:

#### 1. Negative Beta Emission
In negative beta emission, \(^{40}K\) decays into \(^{40}Ca\) (Calcium-40) and an electron (beta particle). The reaction can be written as:
\[
^{40}K \rightarrow ^{40}Ca + e^- + \bar{\nu}
...