`.^(12)N` beta decays to an ecited state of `.^(12)C`, which subsequenctly decays to the ground state with the emission of a `4.43 -MeV` gamma ray. What is the maxium kinetic energy of the emitted beta particle?

Explanation

To solve the problem, we need to calculate the maximum kinetic energy of the emitted beta particle during the decay process. Here are the steps to arrive at the solution:

### Step 1: Understand the Decay Process
The question states that Nitrogen-12 (N) undergoes beta decay to an excited state of Carbon-12 (C), which then emits a gamma ray to transition to its ground state.

### Step 2: Determine the Mass of the Excited State
The mass of the excited state of Carbon-12 can be calculated using the energy of the emitted gamma ray. The mass-energy equivalence principle states that energy can be converted to mass using the equation \( E = mc^2 \). The energy of the gamma ray is given as 4.43 MeV.

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