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How much energy must a bomberding proton...

How much energy must a bomberding proton possess to cause the reaction `._(3)Li^(7) + ._(1)H^(1) rarr ._(4)Be^(7) + ._(0)n^(1)`
(Mass of `._(3)Li^(7)` atom is `7.01400`, mass of `._(1)m^(1)` atom is `1.0783` , mass of `._(4)Be^(7)` atom is `7.01693`)

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AI Generated Solution

To find out how much energy a bombarding proton must possess to cause the reaction \( _{3}^{7}\text{Li} + _{1}^{1}\text{H} \rightarrow _{4}^{7}\text{Be} + _{0}^{1}\text{n} \), we will follow these steps: ### Step 1: Calculate the mass of the reactants The reactants in this reaction are lithium and hydrogen. We need to sum their masses: \[ \text{Mass of reactants} = \text{Mass of } _{3}^{7}\text{Li} + \text{Mass of } _{1}^{1}\text{H} \] ...
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