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Wave property of electrons implies that they will show diffraction effects. Davission and Germer demonstrated this by diffracting electrons from crystals. The law governing the diffraction from a crystal is obtained by requiring that electron waves reflected from the planes of atoms in a crystal interfere constructively (see figure)

The surface of a metal is illuminated with the light of `400 nm`. The kinetic energy of the ejected photoelectrons was found to be `1.68 eV`. The work function of the metal is : (`hc = 1240 eV-nm`)

A

a) `1.51 eV`

B

b) `1.68 eV`

C

c) `3.09 eV`

D

d) `1.42 eV`

Text Solution

Verified by Experts

The correct Answer is:
D

`E_(k)=(hc)/lambda- phi_(0) implies 1.68 =12400/4000- phi_(0)`
By solving it `" "phi_(0)=1.42 eV`
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The surface of a metal illuminated with the light of 400 nm . The kinetic energy of the ejected photoelectrons was found to be 1.68 eV . The work function of the metal is : (hc=1240 eV.nm)

Wave property of electron implies that they will show diffraction effected . Davisson and Germer demonstrated this by diffracting electron from crystals . The law governing the diffraction from a crystals is obtained by requiring that electron waves reflected from the planes of atoms in a crystal inter fere constructiely If a strong diffraction peak is observed when electrons are incident at an angle i from the normal to the crystal planes with distance d between them (see fig) de Brogle wavelength lambda_(dB) of electrons can be calculated by the relationship (n is an intenger)

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