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If N(0) is the initial mass of a substan...

If `N_(0)` is the initial mass of a substance with half-life `t_(1//2) = 5` years, then the amount of substance left after 15 years is

A

`(N_(0))/(8)`

B

`(N_(0))/(16)`

C

`(N_(0))/(2)`

D

`(N_(0))/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A

`N/N_(0)=(1/2)^(n)` where n are is number of half-lives. If `T_(1//2)=5` years then in `15` years, `n=3`
`implies N/N_(0)=(1/2)^(3)=1/8 implies N=N_(0)/8`
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